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Sredni Vashtar Character Analysis Video

Electrical Engineering Stack Exchange is a question and answer site for electronics and electrical engineering professionals, students, and enthusiasts. It only https://amazonia.fiocruz.br/scdp/essay/essay-writing-format-cbse-class-12/grant-date-fair-value.php a minute to sign up. We know that electrons move from the negative to positive terminal, and that holes flow in the conventional direction of current - from the positive to negative terminal.

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Srwdni always assumed that this means that electric signals travel in the conventional current direction and that it's the travel of holes that gets close to the speed of light. Upon further research I come across mentions of electric signals being the electromagnetic waves traveling through the medium by the excitation of the electrons.

This begs the question. If electric signals are the propagation of EM waves at close to c in which direction do these waves travel? In the conventional direction? In the Vasgtar of electron flow? In both directions? But I'm not sure. Note: This merely presents an experiment to perhaps clarify the intent of the question above.

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I'd accept answers that don't address this part of the question. Note that you can treat this as a thought experiment but I think it's possible to physically set up this circuit. The only problem is we'd have to deal with resistance in the real world. Consider a circuit that has 3km of conductors. We start check this out a DC source attached to 1km of conductor. For simplicity you can assume that the conductor has zero resistance. We attach an LED at the end of the conductor. Then we complete the circuit with 2km Sredni Vashtar Character Analysis conductor back to the DC source:.

Assume the wires are spooled so that physically the light bulb and the switch are next to each other. Does it make a difference if the wires are not spooled but are physically laid out over the 1. Does the physical geometry make a difference eg. The best example might be an Ethernet cable. A bit Sredni Vashtar Character Analysis represented as a pulse.

To transmit this pulse, the driving chip puts one output low and another high briefly. If it left them like that, then a conventional circuit would be formed with current flowing in a loop between them through the termination resistor on the other end. However, it does not, it quickly let's say one nanosecond moves the drivers back to equal voltages.

This launches a rising source on the positive transmit wire and a falling edge in the negative transmit wire.

If you have a fast enough oscilloscope clipped to the wire, these will appear as voltages, but really they're a small EM pulse travelling down the wire. Each pulse also radiates an EM wave outside the conductor. Because the wires are twisted together at Charactdr constant distance, the "positive" wave emitted almost completely cancels the "negative" wave emitted.]